Question

Evaluate:

$\int \frac{\sin \left(\log x\right)}{x}dx$

Answer 1

Now,

$\int \frac{\sin \left(\log x\right)}{x}dx$

$=\int \sin \left(\log x\right)d\left(\log x\right)$

$=-\cos \left(\log x\right)+c$. [ Where $c$ is integrating constant]