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Question

Evaluate x2+3xx2+5x+6dx
(where C is constant of integration)

A
x2ln|x+2|+C
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B
x+2ln|x+2|+C
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C
x2ln|x+2|+C
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D
x+2ln|x+2|+C
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Solution

The correct option is A x2ln|x+2|+C
Let I=x2+3xx2+5x+6dx
I=x(x+3)(x+2)(x+3)dx=xx+2dx
I=x+22x+2dx=dx2dxx+2
I=x2ln|x+2|+C

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