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Question

Evaluate
x2sin1x(1x2)3/2dx

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Solution

According to question,
Let, sin1x=t

=> 11x2dx=dt And, x2=sin2t

Substituting these values, we get
t.sin2t1sin2tdt


t.sin2tcos2tdt
t.tan2tdt
Solving By parts,

=> ttan2t.dttan2tdt

=>t.tantt2(tantt)dt

=> t.tantt2+ln|cost|+t22+C

Replace value of t,

=> sin1x.tan(sin1x)+ln|cos(sin1x)|(sin1x)22+C

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