wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate x3(x1)(x2)dx

Open in App
Solution

x3(x1)(x2)dx

x3x23x+2dx

(1+3x2x23x+2)dx

1dx+3x2(x1)(x2)dx

This can be written as

1dx+(1x1+4x2)dx

1dx+1x1dx+4x2dx

xlog|x+1|+4log|x2|

Therefore, x3(x1)(x2)dx=xlog|x+1|+4log|x2|

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Partial Fractions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon