Evaluate- - eex - ex - dx

∫ e^e^x . e^x . dx =∫ d(e^e^x) =e^e^x+c [ c being integrating costant] ...

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Byju's Answer

Standard XII

Mathematics

Integration by Substitution

Evaluate: ∫...

Question

Evaluate:
$\int e^{e^{x}} . e^{x} . d x$

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Solution

$\int e^{e^{x}} . e^{x} . d x$
$= \int d (e^{e^{x}})$
$= e^{e^{x}} + c$ [ $c$ being integrating costant]

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Evaluate: ∫eex.ex.dx

∫eex.ex.dx=∫d(eex)=eex+c [c being integrating costant]

Evaluate:
$\int e^{e^{x}} . e^{x} . d x$

$\int e^{e^{x}} . e^{x} . d x$
$= \int d (e^{e^{x}})$
$= e^{e^{x}} + c$ [ $c$ being integrating costant]