Consider the given integral.
I=∫2t3t+4dt
I=23∫⎛⎜ ⎜ ⎜ ⎜⎝1−431(t+43)⎞⎟ ⎟ ⎟ ⎟⎠dt
I=23∫1dt−89∫1(t+43)dt
I=23t−89ln(t+43)+C
Hence, this is the answer.
Find limt→4t−√3t+44−t