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Question

Evaluate: cos2x+2sin2xcos2xdx

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Solution

Now,
cos2x+2sin2xcos2xdx
=cos2x+1cos2xcos2xdx [ Since 1cos2x=2sin2x]
=1cos2xdx
=sec2xdx
=tanx+c. [ Where c is integrating constant]

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