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Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
Evaluate: ∫...
Question
Evaluate:
∫
e
x
(
1
+
x
)
d
x
sin
2
(
x
e
x
)
A
cot
(
x
e
x
)
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B
−
cot
(
x
e
x
)
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C
−
tan
(
x
e
x
)
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D
−
cot
(
e
x
)
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Solution
The correct option is
A
−
cot
(
x
e
x
)
Substitute
x
e
x
=
t
∴
(
1.
e
x
+
x
.
e
x
)
d
x
=
d
t
Thus,
I
=
∫
c
o
sec
2
t
d
t
=
−
cot
t
+
c
=
−
cot
(
x
e
x
)
+
c
.
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Similar questions
Q.
∫
e
x
1
+
x
cos
2
x
e
x
d
x
=
(a) 2 log
e
cos (xe
x
) + C
(b) sec (xe
x
) + C
(c) tan (xe
x
) + C
(d) tan (x + e
x
) + C
Q.
equals
A. − cot (
ex
x
) + C
B. tan (
xe
x
) + C
C. tan (
e
x
) + C
D. cot (
e
x
) + C