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Byju's Answer
Standard XII
Mathematics
Integration Using Substitution
Evaluate: ∫π...
Question
Evaluate:
∫
π
4
0
e
sin
x
(
1
+
tan
x
sec
x
)
d
x
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Solution
given,
∫
π
4
0
e
sin
x
(
1
+
tan
x
sec
x
)
d
x
Let
e
sin
x
sec
x
=
z
or,
d
z
=
(
e
sin
x
.
cos
x
.
sec
x
+
e
sin
x
sec
x
.
tan
x
)
d
x
or,
d
z
=
e
sin
x
(
1
+
sec
x
.
tan
x
)
d
x
So the given integration will take the form
⇒
∫
π
4
0
d
(
e
sin
x
sec
x
)
=
[
e
sin
x
sec
x
]
π
4
0
=
(
√
2
e
1
√
2
−
1
)
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