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Question

Evaluate: sin2x(1+sinx)(2+sinx)dx

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Solution

Consider, I=sin2x(1+sinx)(2+sinx)

I=2sinxcosx(1+sinx)(2+sinx)

Let sinx=t
Differentiate wrt x
cosxdx=dt

I=2t(1+t)(2+t)

I=A(1+t)+B(2+t)

Using method of partial fractions,we get,

A=2,B=4

I=2(1+t)+4(2+t)

I=2ln|1+t|+4ln|2+t|+C

I=ln(2+t)4(1+t)2+C

I=ln(2+sinx)4(1+sinx)2+C

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