CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate : (a+xax+axa+x)dx

A
2sin1(xa)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2asin1(xa)+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2cos1(xa)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2acos1(xa)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2asin1(xa)+c

Given, I= axa+x+a+xaxdx

=(a+x)+(ax)a2x2dx

=2aa2x2dx

=2.sin1xa.(a)+c

=2a.sin1xa+c


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definite Integral as Limit of Sum
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon