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Question

Evaluate 10x21+x2dx

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Solution

We have,
I=10x21+x2dx

I=10x2+111+x2dx

I=101 dx1011+x2dx

I=[x]10[tan1x]10

I=[10](tan11tan10)

I=1tan1tanπ4+0

I=1π4

Hence, this is the answer.

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