Evaluate:
$1 \int 0 \frac{d x}{1 + x^{2}}$

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Solution

Now,
$1 \int 0 \frac{d x}{1 + x^{2}}$
$= {[{tan}^{- 1} x]}_{0}^{- 1}$
$= \frac{π}{4} - 0$
$= \frac{π}{4}$ .

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