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Question

Evaluate:
π20sinxsinx+cosxdx.

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Solution

Let I= π20sinxsinx+cosxdx......(1)
or, I= π20cosxcosx+sinxdx......(2) [ Using property of definite integral]
Now adding (1) and (2) we get,
2I=π20dx
or, 2I=π2
or, I=π4.

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