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Question

Evaluate :
π/20sinxsinx+cosxdx

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Solution

I=π/20sinxsinx+cosxdx ........(1)

I=π/20cosxsinx+cosxdx ......(2) (a0f(x)dx=a0f(ax)dx)

Adding 1 and 2, we get,
2I=π/20dx

2I=π2

I=π4

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