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Byju's Answer
Standard XII
Mathematics
Factorization Method Form to Remove Indeterminate Form
Evaluate li...
Question
Evaluate
lim
n
→
∞
[
1
(
n
+
1
)
(
n
+
2
)
+
1
(
n
+
2
)
(
n
+
4
)
+
.
.
.
.
+
1
6
n
2
]
.
Open in App
Solution
lim
n
→
∞
[
1
(
n
+
1
)
(
n
+
2
)
+
1
(
n
+
2
)
(
n
+
4
)
+
.
.
.
+
1
6
n
2
]
lim
n
→
∞
1
n
2
[
1
(
1
+
1
/
n
)
(
1
+
2
/
n
)
+
1
(
1
+
2
/
n
)
(
1
+
4
/
n
)
+
.
.
.
+
1
6
]
as
n
→
∞
,
1
n
→
0
1
n
2
→
0
=
0
[
1
1
×
1
+
1
1
×
1
+
.
.
.
]
=
0
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0
Similar questions
Q.
lim
n
→
∞
n
[
1
(
n
+
1
)
(
n
+
2
)
+
1
(
n
+
2
)
(
n
+
4
)
+
⋯
+
1
6
n
2
]
is equal to
Q.
The value of
lim
n
→
∞
n
[
1
(
n
+
1
)
(
n
+
2
)
+
1
(
n
+
2
)
(
n
+
4
)
+
⋯
+
1
6
n
2
]
=
log
k
, then
2
k
=
Q.
The value of
lim
n
→
∞
[
n
(
n
+
1
)
(
n
+
2
)
+
n
(
n
+
2
)
(
n
+
4
)
+
⋯
+
1
6
n
]
is:
Q.
Assertion :If
f
(
x
)
=
1
n
[
(
n
+
1
)
(
n
+
2
)
(
n
+
3
)
.
.
.
(
n
+
n
)
]
1
n
then
lim
n
→
∞
f
(
x
)
equals
4
e
Reason:
lim
n
→
∞
1
n
f
(
r
n
)
=
∫
1
0
f
(
x
)
d
x
Q.
Let
S
n
=
n
(
n
+
1
)
(
n
+
2
)
+
n
(
n
+
2
)
(
n
+
4
)
+
n
(
n
+
3
)
(
n
+
6
)
+
.
.
.
.
.
.
+
1
6
n
, then
lim
n
→
∞
S
n
is
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