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Question

Evaluate limn0sin2(x+n)sin2(x)n

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Solution

Consider sin2(x+n)sin2xn
Using sin(A+B)sin(AB)=sin2Asin2B
=sin(x+n+x)sin(x+nx)n
=sin(2x+n)sin(n)n
Now, limn0sin(2x+n)sin(n)n
=limn0sin(2x+n)×limn0sinnn
=sin2x×1 since limθ0sinθθ=1
=sin2x

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