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Question

Evaluate
limx01cosxx2

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Solution

Using L' Hospital to limx01cosxx2
Differentiating numerator & denominator =limx01(sinx)2cosx2x
sinx2cosx2x
limx0sinx2x×2cosx
1 as limx0
14cos0
=14.

1198182_1301011_ans_34fae2184a3046778cc970fd5b902d9c.jpg

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