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Question

Evaluate: limx1x151x101

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Solution

We have,
limx1x151x101
Dividing in the numerator and denominator by (x1), we get
limx1(x15115x1)⎜ ⎜limx11(x10110)(x1)⎟ ⎟
=15(1)1410(1)9 [Since, limxaxnanxa=nan1]
=32

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