Question

Evaluate: $\underset{x\to 1}{lim}\frac{2x^2+4x+4}{2x-1}$

• A. 1
• B. 10
• C. 20
• D. 5

Answer 1

The correct option is B 10

Given, $\underset{x\to 1}{lim}\frac{2x^2+4x+4}{2x-1}$
Substituting $x=1$ we get
$\underset{x\to 1}{lim}\frac{2x^2+4x+4}{2x-1}=\frac{2{\left(1\right)}^2+4\left(1\right)+4}{2\left(1\right)-1}=\frac{2+4+4}{2-1}=10$