Evaluate- lim x- 4 x 3 -64 x 2 -16

x→ 4lim( x^3 64x^2 16 )=00 #160;Apply L Hospital rule, x→ 4lim ( 3x^22x )=3× 4^22× 4=6 ...

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Question

Evaluate: $lim x \to 4 (\frac{x^{3} - 64}{x^{2} - 16})$

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