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Byju's Answer
Standard XII
Mathematics
Property 2
Evaluate: l...
Question
Evaluate:
lim
x
→
π
2
1
−
sin
3
x
3
cos
2
x
Open in App
Solution
lim
x
→
π
2
1
−
sin
3
x
3
cos
2
x
=
lim
x
→
π
2
(
1
−
sin
x
)
(
1
+
sin
2
x
+
sin
x
)
3
(
1
−
sin
2
x
)
=
lim
x
→
π
2
(
1
−
sin
x
)
(
1
+
sin
2
x
+
sin
x
)
3
(
1
−
sin
x
)
(
1
+
sin
x
)
=
lim
x
→
π
2
(
1
+
sin
2
x
+
sin
x
)
3
(
1
+
sin
x
)
=
1
+
sin
2
π
2
+
sin
π
2
3
(
1
+
sin
π
2
)
=
1
+
1
+
1
3
(
1
+
1
)
=
3
6
=
1
2
(Ans)
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