wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate limxx2+x+x2+1

Open in App
Solution

limxx2+xx2+1limxx1+xx2x1+1x2limx(1+12x112x2)limx12x12x212=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative of Simple Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon