Evaluate each of the following
2sin2 30o−3cos2 45o+tan2 60o
= 2×(12)² - 3×1√2)² + ( √3)²
= 12 - 32 + 3
= 3-1
= 2
tan2 60o+4cos2 45o+3sec2 30o+5 cos2 90ocosec 30o+sec60o−cot2 30o
tan2 30o+tan2 60o+tan2 45o