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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Compound Angles
Evaluate each...
Question
Evaluate each of the following:
(i)
cot
-
1
1
3
-
cosec
-
1
-
2
+
sec
-
1
2
3
(ii)
cot
-
1
2
cos
sin
-
1
3
2
(iii)
cosec
-
1
-
2
3
+
2
cot
-
1
-
1
(iv)
tan
-
1
-
1
3
+
cot
-
1
1
3
+
tan
-
1
sin
-
π
2
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Solution
(i)
cot
-
1
1
3
-
cosec
-
1
-
2
+
sec
-
1
2
3
=
cot
-
1
cot
π
3
-
cosec
-
1
cosec
-
π
6
+
sec
-
1
sec
π
6
=
π
3
+
π
6
+
π
6
=
2
π
3
(ii)
cot
-
1
2
cos
sin
-
1
3
2
=
cot
-
1
2
cos
sin
-
1
sin
π
3
=
cot
-
1
2
cos
π
3
=
cot
-
1
2
×
1
2
=
cot
-
1
1
=
cot
-
1
tan
π
4
=
π
4
(iii)
cosec
-
1
-
2
3
+
2
cot
-
1
-
1
=
cosec
-
1
cosec
-
π
3
+
2
cot
-
1
cot
3
π
4
=
-
π
3
+
2
×
3
π
4
=
-
π
3
+
3
π
2
=
7
π
6
(iv)
tan
-
1
-
1
3
+
cot
-
1
1
3
+
tan
-
1
sin
-
π
2
=
tan
-
1
tan
-
π
6
+
cot
-
1
cot
π
3
+
tan
-
1
-
1
=
tan
-
1
tan
-
π
6
+
cot
-
1
cot
π
3
+
tan
-
1
tan
-
π
4
=
-
π
6
+
π
3
-
π
4
=
-
π
12
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Similar questions
Q.
Evaluate each of the following:
(i)
cot
-
1
1
3
-
cosec
-
1
-
2
+
sec
-
1
2
3
(ii)
cot
-
1
2
cos
sin
-
1
3
2
(iii)
cosec
-
1
-
2
3
+
2
cot
-
1
-
1
(iv)
tan
-
1
-
1
3
+
cot
-
1
1
3
+
tan
-
1
sin
-
π
2
Q.
Evaluate:
sec
2
(
tan
−
1
2
)
+
c
o
s
e
c
2
(
cot
−
1
3
)
Q.
tan A / 1- cot A + cot A / 1- tan A = 1+ sec A cosec A.
Q.
(i)
cosecθ
+
cotθ
cosecθ
-
cotθ
=
(
cosecθ
+
cotθ
)
2
=
1
+
2
cot
2
+
2
cosecθ
cotθ
(ii)
secθ
+
tanθ
secθ
-
tanθ
=
(
secθ
+
tanθ
)
2
=
1
+
2
tan
2
θ
+
2
secθ
tanθ
Q.
Evaluate:
(
1
+
tan
θ
+
sec
θ
)
(
1
+
cot
θ
−
c
o
s
e
c
θ
)
=
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