Evaluate each of the following
sin 30osin 45o+tan 45osec 60o−sin 60osin 45o−sin 30osin 90o
sin 30osin 45o+tan 45osec 60o−sin 60osin 45o−sin 30osin 90o
=sin 30osin 45o+tan 45o cos 60o−sin 60osin 45o−sin 30osin 90o
=(12)(1√2)+1×12−(√32)(1√2)−(12)1
=1√2+12−√32−12
=1−√3√2