Evaluate each of the following tan-45o-cosec-30o-sec-60o-cot-45o-5-sin-90o-2-cos-0o

Tan 45^o/cosec 30^o+sec 60^o/cot 45^o 5 sin 90^o/2 cos 0^o =tan 45^o sin 30^o + tan 45^o/cos 60^o 5 sin 90^o/2 cos 0^o = 1 ×1/2 + 1/ (1/2 ) 5 × 1/2 × 1 =1/2 ...

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Byju's Answer

Standard X

Mathematics

Standard Values of Trigonometric Ratios

Evaluate each...

Question

Evaluate each of the following

$\frac{t a n 45^{o}}{c o s e c 30^{o}} + \frac{s e c 60^{o}}{c o t 45^{o}} - \frac{5 s i n 90^{o}}{2 c o s 0^{o}}$

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Solution

$\frac{t a n 45^{o}}{c o s e c 30^{o}} + \frac{s e c 60^{o}}{c o t 45^{o}} - \frac{5 s i n 90^{o}}{2 c o s 0^{o}}$

$= t a n 45^{o} s i n 30^{o} + \frac{t a n 45^{o}}{c o s 60^{o}} - \frac{5 s i n 90^{o}}{2 c o s 0^{o}}$

$= 1 \times \frac{1}{2} + \frac{1}{(\frac{1}{2})} - \frac{5 \times 1}{2 \times 1}$

$= \frac{1}{2} + 2 - \frac{5}{2} = 0$

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Evaluate each of the following tan 45ocosec 30o+sec 60ocot 45o−5 sin 90o2 cos 0o

tan 45ocosec 30o+sec 60ocot 45o−5 sin 90o2 cos 0o =tan 45osin 30o+tan 45ocos 60o−5 sin 90o2 cos 0o =1×12+1(12)−5×12×1 =12+2−52=0

Evaluate each of the following

$\frac{t a n 45^{o}}{c o s e c 30^{o}} + \frac{s e c 60^{o}}{c o t 45^{o}} - \frac{5 s i n 90^{o}}{2 c o s 0^{o}}$