Evaluate each of the following:(i) 23−35
(ii) −47−2(−3)
(iii) 47−(−5)(−7)
(iv) −21−59
We have
(i) 23−35=2×5−3×315=10−915=115
(ii) −47−2(−3)=−4×3+2×721=−12+1421=221(iii) 47−(−5)(−7)=4−57=−17
(iv) −21−59=−2×9−59=−18−59=−239