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Question

Evaluate each of the following:
(i) 2335

(ii) 472(3)

(iii) 47(5)(7)

(iv) 2159

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Solution

We have

(i) 2335=2×53×315=10915=115

(ii) 472(3)=4×3+2×721=12+1421=221
(iii) 47(5)(7)=457=17

(iv) 2159=2×959=1859=239


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