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Question

Evaluate each of the following:

(i) cot-1cotπ3
(ii) cot-1cot4π3
(iii) cot-1cot9π4
(iv) cot-1cot19π6
(v) cot-1cot-8π3
(vi) cot-1cot21π4

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Solution

We know that

cot-1cotθ=θ, ( 0, π)

(i) We have
cot-1cotπ3=π3
(ii) We have
cot-1cot4π3=cot-1cotπ+π3=cot-1cotπ3=π3
(iii) We have
cot-1cot9π4=cot-1cot2π+π4=cot-1cotπ4=π4
(iv) We have
cot-1cot19π6=cot-1cotπ+π6=cot-1cotπ6=π6
(v) We have
cot-1cot-8π3=cot-1-cot8π3=cot-1-cot3π-π3=cot-1cotπ3=π3
(vi) We have
cot-1cot21π4=cot-1cot5π+π4=cot-1cotπ4=π4

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