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Question

Evaluate each of the following using suitable identities.
(1)(104)3
(2)(999)3

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Solution

(1) (104)3=(100+4)3 [Now (a+b)3=a3+3a2b+3ab2+b3]

=(100)3+3(100)2(4)+3(100)(4)2+43

=1000000+3×10000×4+3×100×16+64

=1000000+120000+4800+64

=1124864

(2) (999)3=(10001)3 (ab)3=a33a2b+3ab2b3

=(1000)33(1000)2(1)+3(1000)(1)2(1)3

=10000000003×1000000+3×10001

=997,002,999

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