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Question

Evaluate each of the following using suitable identities.
(103)3

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Solution

We know that (x+y)3=x3+y3+3xy(x+y)
(103)3=(100+3)3
Here x=100 and y=3
(100)3+(3)3+3(100)(3)(100+3)
=1000000+27+900(100+3)
=1000000+27+90000+2700
=1092727


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