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Question

Evaluate 2x2+5x32x2+7x6÷2x2+5x32x2x6

A
x2x+2
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B
x+2x2
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C
2x+3x+2
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D
2x+32x3
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Solution

The correct option is A x2x+2
2x2+5x32x2+7x+6÷2x2+5x32x2x6

= 2x2+5x32x2+7x+6×2x2x62x2+5x3

Cancelling 2x2+5x3 from numerator and denominator.

= 2x2x62x2+7x+6

= (x2)(2x+3)(x+2)(2x+3)

= x2x+2

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