Question

Evaluate $:$$\frac{4}{3}$$-$$\frac{1}{4}$using number line

Answer 1

Step 1: The bottom numbers are different, To make it same take the L.C.M of 3 and 4

L.C.M of $3$and $4$ is $12$

Step 2: Convert both the fraction into equivalent like fractions with their L.C.M as common denominator

$\frac{4}{3}$$=$$\frac{4\times 4}{3\times 4}$ $=$$\frac{16}{12}$

$\frac{1}{4}$$=$$\frac{1\times 3}{4\times 3}$ $=$$\frac{3}{12}$

Step 3: Subtract the numerators and put the answer over the denominator

$\frac{16}{12}$$-$$\frac{3}{12}$ $=$$\frac{13}{12}$

Step 4 : Divide the line segment between the points 0 and 1,1 and 2 into 12 equal parts each ( Denominator is 12)

Step 5 :Each part will represent $\frac{1}{12}$

Step 6 :Label the points $\frac{1}{12}$$,$$\frac{2}{12}$$,$ $\frac{3}{12}$$,$$\frac{4}{12}$$,$ $\frac{5}{12}$$,$ $\frac{6}{12}$$,$$\frac{7}{12}$$,$$\frac{8}{12}$ $,$$\frac{9}{12}$$,$$\frac{10}{12}$$,$ $\frac{11}{12}$between the points 0 and 1, $\frac{13}{12}$$,$$\frac{14}{12}$$,$ $\frac{15}{12}$$,$$\frac{16}{12}$between the points 1 and 2 on the number line

Step 7 : Move sixteen parts on the right side of zero to reach $\frac{16}{12}$

Step 8 : Move three parts on the left side of $\frac{16}{12}$to reach $\frac{13}{12}$