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Byju's Answer
Standard X
Mathematics
Square Root of Polynomials
Evaluate 6x2 ...
Question
Evaluate
6
x
2
−
x
−
2
8
x
2
+
6
x
+
1
×
12
x
2
−
13
x
−
4
12
x
2
−
25
x
+
12
[3 Marks]
Open in App
Solution
6
x
2
−
x
−
2
8
x
2
+
6
x
+
1
×
12
x
2
−
13
x
−
4
12
x
2
−
25
x
+
12
=
(
3
x
−
2
)
(
2
x
+
1
)
(
2
x
+
1
)
(
4
x
+
1
)
×
(
4
x
+
1
)
(
3
x
−
4
)
(
4
x
−
3
)
(
3
x
−
4
)
[1 Mark]
=
(
3
x
−
2
)
(
2
x
+
1
)
(
4
x
+
1
)
(
3
x
−
4
)
(
2
x
+
1
)
(
4
x
+
1
)
(
4
x
−
3
)
(
3
x
−
4
)
[1 Mark]
Cancelling
(
2
x
+
1
)
(
4
x
+
1
)
(
3
x
−
4
)
from numerator and denominator
=
3
x
−
2
4
x
−
3
[1 Mark]
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0
Similar questions
Q.
Factorise:
12
(
x
2
+
7
x
)
2
-
8
(
x
2
+
7
x
)
(
2
x
-
1
)
-
15
(
2
x
-
1
)
2
.
Q.
Mark the correct alternative in the following question:
What should be added to 3x
2
+ 4 to get 9x
2
-
7?
(a) 6x
2
-
11 (b) 6x
2
+ 11 (c) 12x
2
-
11 (d) 12x
2
+ 11
Q.
Evaluate
6
x
2
−
x
−
2
8
x
2
+
6
x
+
1
×
12
x
2
−
13
x
−
4
12
x
2
−
25
x
+
12
Q.
Solve for
x
:
6
x
2
+
13
x
−
4
2
x
+
5
=
12
x
2
+
5
x
−
2
4
x
+
3
Q.
Solve the folowing equation:
6
x
2
+
13
x
−
4
2
x
+
5
=
12
x
2
+
5
x
−
2
4
x
+
3
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