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Question

Evaluate 6x2x28x2+6x+1×12x213x412x225x+12 [3 Marks]

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Solution

6x2x28x2+6x+1×12x213x412x225x+12

= (3x2)(2x+1)(2x+1)(4x+1)×(4x+1)(3x4)(4x3)(3x4) [1 Mark]

= (3x2)(2x+1)(4x+1)(3x4)(2x+1)(4x+1)(4x3)(3x4) [1 Mark]

Cancelling (2x+1)(4x+1)(3x4) from numerator and denominator

= 3x24x3 [1 Mark]

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