Evaluate 8a3 - 27b3-64x3 - y3- where 64x3 - y3 - 0-

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Algebraic Identities

Evaluate 8a3 ...

Question

Evaluate $\frac{(8 a^{3} - 27 b^{3})}{(64 x^{3} + y^{3})}$ , where $(64 x^{3} + y^{3}) \neq 0$ .

\frac{(2 a - 3 b) (4 a^{2} + 6 a b + 9 b^{2})}{(4 x + y) (16 x^{2} - 4 x y + y^{2})}

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\frac{(2 a - 3 b) (4 a^{2} + 6 a b + 9 b^{2})}{(4 x - y) (16 x^{2} - 4 x y + y^{2})}

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\frac{(2 a + 3 b) (4 a^{2} + 6 a b + 9 b^{2})}{(4 x + y) (16 x^{2} - 4 x y + y^{2})}

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\frac{(2 a + 3 b) (4 a^{2} + 6 a b + 9 b^{2})}{(4 x - y) (16 x^{2} - 4 x y + y^{2})}

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Similar questions

Evaluate $\frac{(8 a^{3} - 27 b^{3})}{(64 x^{3} + y^{3})}$ , where $(64 x^{3} + y^{3}) \neq 0$ .

\frac{27}{p^{3}}

\frac{128}{b^{3}}

y^{3} - 27

x^{3} - {64 y}^{3}

{27 m}^{3} - {216 n}^{3}

{8 p}^{3} - \frac{27}{p^{3}}

{343 a}^{3} - {512 b}^{3}

{64 x}^{3} - {729 y}^{3}

Verify:

x³+ y³+ z³- 3xyz =(x+y+z) [(x-y)² + (y-z)² +(z-x)²] and a factor of 64x³+125y³ -64³+ 240.

Evaluate $(8 a^{3} - 27 b^{3})$ if $\frac{a}{b} = \frac{3}{2}$

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