Question

Evaluate :
i) $(0.9{)}^2$

Answer 1

Step: Evaluate
Given : $(0.9{)}^2$
$\Rightarrow 0.9\times 0.9$
$\Rightarrow 9\times 9$
$=81$
$0.9$ has $1$ decimal place and is multiplied twice. So, their product will have $1+1=2$ decimal places.
$\therefore (0.9{)}^2=0.81$