Question

Evaluate:

(i) (1.2)²
(ii) (0.7)²
(iii) (0.04)²
(iv) (0.11)²

Answer 1

(i) (1.2)² = 1.2 $\times$ 1.2
First, we will find the product 1.2 $\times$ 1.2.
Now, 12 $\times$ 12 = 144
Sum of decimal places in the given numbers = (1 + 1) = 2
So, the product must have two decimal places.

∴ (1.2)² = 1.2$\times$ 1.2 = 1.44

(ii) (0.7)² = 0.7 $\times$ 0.7
First, we will find the product 0.7 $\times$ 0.7.
Now, 7 $\times$ 7 = 49
Sum of decimal places in the given numbers = (1 + 1) = 2
So, the product must have two decimal places.
∴ (0.7)² = 0.7 $\times$ 0.7 = 0.49

(iii) (0.04)² = 0.04 $\times$ 0.04
First, we will find the product 0.04 $\times$ 0.04.
Now, 4$\times$ 4 = 16
Sum of decimal places in the given numbers = (2 + 2) = 4
So, the product must have four decimal places.
∴ (0.04)² = 0.04$\times$ 0.04 = 0.0016

(iv) (0.11)² = 0.11 $\times$ 0.11
First, we will find the product 0.11 $\times$ 0.11.
Now, 11 $\times$ 11 = 121
Sum of decimal places in the given numbers = ( 2 + 2) = 4
So, the product must have four decimal places.
∴ (0.11)² = 0.11 $\times$ 0.11 = 0.0121