The correct option is A 0 i^24 + (1i)^26 i^4 = 1 = 1 + 1i^2 = i^2 +1i^2 #160; = 0 #160; (As i^2 = 1 ) ...

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Algebra of Complex Numbers

Evaluate: i...

Question

Evaluate: $i^{24} + {(\frac{1}{i})}^{26}$

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Solution

The correct option is A $0$
$i^{24} + (\frac{1}{i})^{26}$
$i^{4} = 1$
$= 1 + \frac{1}{i^{2}}$
$= \frac{i^{2} + 1}{i^{2}} = 0$ (As $i^{2} = - 1$ )

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