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Question

Evaluate :
(i) (2x+3y)2 (ii) (2x3y)2 (iii) (2x+3y)(2x3y)

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Solution

(i) We have,
(2x+3y)2=(2x)2+2×(2x)×(3y)+(3y)2 [Using : (a+b)2=a2+2ab+b2]
= 4x2+12xy+9y2

(ii) We have,
(2x3y)2=(2x)22×(2x)×(3y)+(3y)2 [Using : (ab)2=a22ab+b2]
= 4x212xy+9y2

(iii) We have,
(2x+3y)(2x3y)=(2x)2(3y)2 [Using : (a+b)(ab)=a2b2]
4x29y2.

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