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Question

Evaluate:

(i) 34-45
(ii) -3-47
(iii) 724-1936
(iv) 1415-1320
(v) 49-2-3
(vi) 711--4-11
(vii) -514--27
(viii) -5-8--34

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Solution


( i)34-45=34-45=34+additive inverse of 45L.C.M. 4 and 5 is 20. =15-1620=-120


(ii)-31-47=-31+additive inverse of 47=-31-47 =-21-47 =-257

(iii) 724-1936= 724+additive inverse of 1936= 724-1936 L.C.M. of 24 and 36 is 72.=21-3872=-1772

(iv) 1415-1320=1415+additive inverse of 1320=1415-1320 L.C.M. of 15 and 20 is 60.=56-3960=1760

(v)49-2(-3)We need a positive denominator.2-3×(-1)(-1)=-2349-(-2)3 =49+ additive inverse of -23L.C.M. of 3 and 9 is 9.=4+69=109

(vi)711-(-4)(-11)We need a positive denominator. -4-11×(-1)(-1)=411711-411=711+additive inverse of411 =7-411=311
(vii) -514--27=-514+additive inverse of -27-514+27L.C.M. of 14 and 7 is 14.-5+414=-114




(viii)-5-8--34 We need a positive denominator. -5-8×-1-1=5858-(-3)4 =58+ additive inverse of -34L.C.M. of 8 and 4 is 8.=5+68=118 [L.C.M. of 8 and 4 is 8.]

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