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Byju's Answer
Standard VII
Mathematics
Addition of Integers
Evaluatei 421...
Question
Evaluate
(i)
4
216
-
2
3
+
1
256
-
3
4
+
2
243
-
1
5
(ii)
64
125
-
2
3
+
256
625
-
1
4
+
3
7
0
(iii)
81
16
-
3
4
25
9
-
3
2
÷
5
2
-
3
(iv)
25
5
2
×
729
1
3
125
2
3
×
27
2
3
×
8
4
3
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Solution
(i)
4
216
-
2
3
+
1
256
-
3
4
+
2
243
-
1
5
4
216
-
2
3
+
1
256
-
3
4
+
2
243
-
1
5
=
4
6
3
-
2
3
+
1
4
4
-
3
4
+
2
3
5
-
1
5
=
4
6
-
2
+
1
4
-
3
+
2
3
-
1
=
4
6
2
+
4
3
+
2
3
=
144
+
64
+
6
=
214
(ii)
64
125
-
2
3
+
256
625
-
1
4
+
3
7
0
64
125
-
2
3
+
256
625
-
1
4
+
3
7
0
=
4
5
3
-
2
3
+
4
5
4
-
1
4
+
1
=
4
5
-
2
+
4
5
-
1
+
1
=
5
4
2
+
5
4
+
1
=
25
16
+
5
4
+
1
=
25
+
20
+
16
16
=
61
16
(iii)
81
16
-
3
4
25
9
-
3
2
÷
5
2
-
3
81
16
-
3
4
25
9
-
3
2
÷
5
2
-
3
=
16
81
3
4
9
25
3
2
÷
2
5
3
=
2
3
4
3
4
3
5
2
3
2
÷
8
125
=
2
3
3
3
5
3
÷
8
125
=
8
27
×
27
125
8
125
=
1
(iv)
25
5
2
×
729
1
3
125
2
3
×
27
2
3
×
8
4
3
25
5
2
×
729
1
3
125
2
3
×
27
2
3
×
8
4
3
=
5
2
5
2
×
9
3
1
3
5
3
2
3
×
3
3
2
3
×
2
3
4
3
=
5
5
×
9
1
5
2
×
3
2
×
2
4
=
5
×
5
×
5
×
5
×
5
×
9
5
×
5
×
3
×
3
×
2
×
2
×
2
×
2
=
125
16
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Q.
Simplify:
(i)
3
2
+
2
2
×
1
2
3
(ii)
3
2
-
2
2
×
2
3
-
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(iii)
1
3
-
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-
1
2
-
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÷
1
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-
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(iv)
2
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+
3
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-
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÷
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2