Question

Evaluate:
(i) (49)^1/2
(ii) (125)^1/3
(iii) (64)^1/6

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right){\left(49\right)}^{\frac{1}{2}}={\left(7^2\right)}^{\frac{1}{2}}=7^{2\times \frac{1}{2}}=7 \\ \left(\mathrm{ii}\right){\left(125\right)}^{\frac{1}{3}}={\left(5^3\right)}^{\frac{1}{3}}=5^{3\times \frac{1}{3}}=5 \\ \left(\mathrm{iii}\right){\left(64\right)}^{\frac{1}{6}}={\left(2^6\right)}^{\frac{1}{6}}=2^{6\times \frac{1}{6}}=2 \end{gathered}$$