Evaluate:
(i) 5−2
(ii) (−3)2
(iii) (13)−4
(iv) (−12)−1
(i) Given 5−2=152 [Since, a−n=1an]
=125
(ii) (−3)2=132 [Since, a−n=1an]
=19
(iii) Given (13)−4=1(13)4
=1181
=81
(iv) Given (−12)−1= 1(−12) [Since, a−1=1a1]
=−2