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Question

Evaluate
(i) 5! (ii) 7! (iii) 7!5!

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Solution

n!=n(n1)(n2)321
(i) 5!=5×4×3×2×1=120

(ii) 7!=7×6×5×4×3×2×1=5040

(iii) 7!5!=7×6×5×4×3×2×15×4×3×2×1
=5040120
=4920

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