Question

Evaluate $I={\int }_0^{2}2tdt$

• A. $4$
• B. $8$
• C. $2$
• D. $1$

Answer 1

The correct option is A $4$

Given : $I={\int }_0^{2}2tdt$

The value of upper limit is $2$ and that of the lower limit is $0$.

Integerating the given equation:

$I=2{\int }_0^{2}t$

$I=2\times {\left[\frac{t^2}{2}\right]}_0^2$

Substuting the value of t we get,

$I=2\left(\frac{2^2}{2}\right)$

$I=4$