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Question

Evaluate: I=ex(1+ex)(2+ex) dx

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Solution

ex(1+ex)(x+ex)dxLet,1+ex=tdtdx=ex=dtt(t+1)=dtt2+t=dt(t+12)2(12)2=12×12ln∣ ∣(t+12)12(t+12)+12∣ ∣+C=lntt+1+CI=ln1+ex2+ex+C

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