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Question

Evaluate:
i. π20(sin x + cos x)dx
ii. 10(3x2+4)dx
iii. 10(3e3x+ex)dx

A
i. 0; ii. 5; iii. e41e
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B
i. 0; ii. 5; iii. e31
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C
i. 2; ii. 5; iii. e31
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D
i. 2; ii. 5; iii. e41e
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Solution

The correct option is D i. 2; ii. 5; iii. e41e
i. π20(sin x + cos x)dx
=[cos x]π20+[sin x]π20=(0+1)+(10)=2

ii. 10(3x2+4)dx=[x3]10+[4x]10=1+4=5

iii.10(3e3x+ex)dx=[e3x]10+[ex]10
(e31)+(1e+1)=e41e

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