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Question

Evaluate:
i. (sinx+cosx)dx
ii. (3x2+4)dx

A
i.cosx+sinx+C
ii.x3+4x+C
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B
i.cosxsinx+C
ii.x32x+C
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C
i.cosxsinx+C
ii.x3+2x+C
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D
i.cosx+sinx+C
ii.x34x+C
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Solution

The correct option is A i.cosx+sinx+C
ii.x3+4x+C
a.(sinx+cosx)dx
=cosx+sinx+C

b.(3x2+4)dx=x3+4x+C

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