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Question

Evaluate:

(i)sin2 30.cos2 45+4tan2 30+12sin2 90+18cot2 60

(ii)tan260+4 sin245+3 sec230+5 cos290cosec30+sec60cot230 [4 MARKS]

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Solution

Solution: 2 Marks each

(i)sin230.cos245+4tan230+12sin290+18cot260

=(12)2.(12)2+4×(13)2+(12)×(1)2+18×(13)2

=(14×12+4×13+12×1+18×13)

=(18+43+12+124)=4824=2


(ii)tan260+4 sin245+3 sec230+5 cos290cosec30+sec60cot230

=(3)2+4×(12)2+3×(23)2+5×022+2(3)2

=(3+4×12+3×43+5×043)=(3+2+4+01)=9

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