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Question

Evaluate :
i) tan1(13)
ii) sin1(12)

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Solution

(1)

Let tan1(13)=x

then,
tanx=13

tanx=tan(π6)

x=π6

tan1(13)=π6

(2)

Let sin1(12)=x

then,
sinx=12

sinx=sin(π6)

x=π6

sin1(12)=π6

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